If a 200 kg man jumps out a plane and the viscosity (friction due to the air) is equal to 25 N*s/m times the speed, then what is the terminal velocity? The terminal velocity is when the man stops accelerating and continues to fall at a constant speed. Draw a picture with your forces.In many cases, there is a frictional force whose magnitude depends on the speed...?
terminal velocity
when 25*V=mg
V=mg/25=78.4 m/sIn many cases, there is a frictional force whose magnitude depends on the speed...?
You can calculate the man's weight in newtons from his mass. At terminal velocity, he will have a constant speed which produces drag equal to his weight. Do the math. For your picture, show the man with an arrow up, representing drag, and an equal size arrow down, representing weight.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment